The pilot of a helicopter plans to release a bucket of water on a forest fire. The height y in feet of the water t seconds after its release is modeled by y = -16t2 - 2t + 400. The horizontal distance x in feet between the water and its point of release is modeled by x = 91t. To the nearest foot, at what horizontal distance from the target should the pilot begin releasing the water? ____ ft.

Question

anonymous · Answer

When the first drop of water touches the target then y=0. Then solve the first quadratic. DDo you want me to solve it? Please let me know. Then you'll get a real part and an imaginary part for t.  Since time can't be imaginary, take the real answer and substitue it in x=91t and get x

anonymous · Answer

yeah, could you please so I can check to see if I'm even close

anonymous · Answer

Sure when solved the first one t=4.93789 or t=-5.062 so neglect the minus answer since time can't be negative

anonymous · Answer

To the nearest foot, at what horizontal distance from the target should the pilot begin releasing the water?

anonymous · Answer

oh now x=91*4.93789 = 449.34799

anonymous · Answer

to the nearest foot 499

anonymous · Answer

is it correct?

anonymous · Answer

Are you ok? did u get it?

anonymous · Answer

no it wasnt

anonymous · Answer

oh yeah 449 is right