Using the alphabets of the word ' BANANA' determine how many words can be formed so that the two N's are not together. (use permutation /combination)
Hi, is it OK if I walk you through the question, or are you just looking for the answer?
i.e. I can help you step by step, or just give you the answer.
Which do you prefer?
steps
OK. First of all, is it Permutations, or is it Combinations?
"I don't know" is OK, you know, just say something :D
permutation
Great! Suppose there wasn't the condition about the two Ns, how many permutations would be possible?
60 ?
Great! Now, try working out the number of permutations where the 2 N's ARE together.
40?
How did you work that out?
(5!/3!)*2 ?
OK, and where did the 5!, the 3! and the *2, each come from?
i don't know
Don't worry, I'm not suggesting that anything is right/wrong, I just need you to explain your steps to me.
If you really don't know, I can do this step for you. Would you like that?
Are you still there JOYAL? (But if you need more time, just say so!)
steps.....
OK. You knew how to work out the 60, earlier on. Now we want to find the permutations if the two N's ARE together. My favourite way of doing this is to imagine them glued together, so they make something a bit like 1 letter M, instead of two letter N's. If you have the letters BAMAA, how many permutations are there?
@BasketWeave 20 ?
Well done! So if there's 60 ways in total of arranging the letters, and 20 of them DO have the two N's together, how many DON'T have the N's together?
@Joyal Was this question confusing?
40
Well done! That's the answer to your original question. Did that all make sense?
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