Question

Find the lim->2 of x^2-4x=4/x^2+3x-10

Answer 1

what happens when you replace x by 2?

Answer 2

i get 0 so need to use L'hopitals

Answer 3

i assume this is
\[\lim_{x\to 2}\frac{x^2-4x+4}{x^2+3x-10}\] and heck no, you do not need l'hopital, although it would work

Answer 4

since 2 gives zero in both the numerator and denominator, you know you can factor each term s
\[(x-2)(\text{something})\] so you can factor and cancel

Answer 5

can u try it using l'hopitals
i got 0/7

Answer 6

\[\frac{(x-2)(x-2)}{(x-2)(x+5)}=\frac{x-2}{x+5}\] replace x by 2, get
\[\frac{0}{7}=0\]

Answer 7

or get
\[\lim_{x\to 2}\frac{2x-4}{2x+3}\] gives the same thing

Answer 8

second one was l'hopital, first one was factor and cancel
your choice

Answer 9

yea thanks

Answer 10

yw

Answer 11

wanna try another...just need confirmations