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lim x->0 for e^2x-1/e^-1
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correction lim x->0 for e^2x-1?e^x-1
oh my instead of ? i meant /
\[\lim_{x\to0}{e^{2x}-1\over e^x-1}\]yes?
yes turning Test
difference of squares
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using l'hopitals i got 2e^2x/e^x what next i know e^x is1 but what about the top derivative plz
or l'hospital or divide top and bottom by e^x many ways to do it...
if you are doing it the l'hospital way then just simplify \[\lim_{x\to0}{2e^{2x}\over e^x}\]and evaluate
ok yes i see that, what will the numerator work out to? i know the denominator is 1
why don't you just simplify it first?\[\lim_{x\to0}{2e^{2x}\over e^x}=\lim_{x\to0}2e^x\]
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i see...thanks
welcome
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