can someone show me how to use extended power rule within the quotient rule for derivative? http://webwork.math.ttu.edu/wwtmp/equations/10/ab7506a44aafa9272098cb86d31c771.png
you want derivative of that?
yes using extended power rule
ive never heard of an extended power rule
that makes two of us haha
h(x) = tan(3x) * (x)^(-2)
the question calls for extended power rule inside quotient rule. I have an example in my book but it docent really make sense
lets see it if you can
if i can derive what you just typed?
recall that a negative exponent is just a fraction in disguise
no, the example ...
\[p(x)=\tan7x/(1-4x)^5\]
and the answer is\[(7(1-4x)\sec^2(7x)+20\tan7x)/(1-4x)^6\]
thats the answer regardless of any extended power rule .. the parts inbetween would shed some light on this enigma :)
its just the chain rule ...
how do i know what to sub for u?
you aint got to sub for anything :/
wait i think i get it. thx
you were apparently taught that derivatives act on a variable; as opposed to a function ...
derivaite of y(x) = y'(x) * x' , but x' wrt x = 1
y = 2x -> y' = 2 really should be taught as y = 2x -> y' = 2x * x' and as long as the derivative is with respect to x then x'=1
the chain rule always pops out a derivative but they simply dont teach that at first ....
if i asked you to take the derivative of: y = 5x^2 + 6 what would you assume?
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