How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen?

Unbalanced equation: C6H6 + O2 → CO2 + H2O

Show, or explain, all of your work along with the final answer.

Question

How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen?

Unbalanced equation: C6H6 + O2 → CO2 + H2O

Show, or explain, all of your work along with the final answer.

rogue · Answer

First write the balanced reaction.$$2C_6H_6 + 15O_2 → 12CO_2 + 6H_2O$$

rogue · Answer

Next convert moles of benzene to moles of water. 6 moles of H2O are produced for every 2 moles of C6H6 according to the reaction. So 3 mol H2O are produced for every 1 mol C6H6.

So 3 x 8.73 mol = 26.19 mol H2O produced.

rogue · Answer

Now convert moles of H2O to grams of H2O. There are 18.0153 grams of H2O in 1 mole H2O. 

26.19 mol H2O x 18.0153 g/mol = 472 g

anonymous · Answer

Wait. Wouldn't it be 8.73/3?|dw:1331407483099:dw|