let f(x) = n^2 + 2n + 4 and g(x) = -3n +2 Fine (g of f)(1)
Find the f(1) and put that result into the function g.
What is the f(1)?
Thats the whole problem. I'm not good with this sort of problem.
Are you sure that the problem is not f(n)?
g(f(1))?
Ok. Brinethery wants to help you now. Good bye.
Lol huh? I was just making sure what it was.
It says find (g o f)(1)
Merts, you mad at me?
@Mertsj do you have any idea of what to next? I'm not sure what they mean by (g of f)1?
Here's the problem http://i1204.photobucket.com/albums/bb402/Libby_Williams/mod2top5quizq16.jpg
Crap, typo on my work. I mean -3(n^2 + 2n + 4) +2
It seems you don't understand yet what a compound function is.
Ooooh okay.
(n^2 + 2n + 4)(-3n +2)
And then plug 1 in?
There is a problem because f(x) means the function whose variable is x and then we are presented with a function whose variable is n.
So what do I do with 8 and -22?
If we assume that is just a typo and it means f(n), then to find the g(f(1)) means replace n in the function f with 1. Take that result and put it into the function g.
@Mertsj http://i1204.photobucket.com/albums/bb402/Libby_Williams/mod2top5quizq16.jpg
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