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OpenStudy (anonymous):
Differentiate: y = (v^3 - 2v[sqrt[v]])/v
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OpenStudy (bahrom7893):
split this up into two fractions, it will become a piece of cake
OpenStudy (bahrom7893):
y = v^2 - 2sqrt(v) y' = 2v - 2*(1/2)*v^(-1/2) = 2x - 1/sqrt(v)
OpenStudy (anonymous):
yeah i got (2v^2 - v^(3/2))/v^2.... so from there how does that equate to 2v - 1/sqrt(v) ?
OpenStudy (bahrom7893):
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