Question

solve this Differential equation by finding Integrating factor
(5xy+4y^2+1)dx+(x^2+2xy)dy=0

Answer 1

ash start

Answer 2

Wasiqss I'm thinking about it, wait for some time:)

Answer 3

I think I'm gonna get disconnected soon, but I'll solve it for you. We'll have power cut now:(

Answer 4

solve it man plz

Answer 5

lalaly any idea? :P

Answer 6

let M=5xy +4y^2+1 N=x^2+2xy
\[M_y=5x+8y\]\[N_x=2x+2y\]
now we ned to find the integratiing factor\[\frac{1}{F} \frac{dF}{dx}=\frac{M_y-N_x}{N}\]\[\frac{1}{F} \frac{dF}{dx}=\frac{5x+8y-(2x+2y)}{x^2+2xy}\]\[\frac{1}{F} \frac{dF}{dx}=\frac{3(x+2y)}{x(x+2y)}\]\[\frac{1}{F} \frac{dF}{dx}=\frac{3}{x}\]integrate to find F which is the integrating factor
Then multiply the whole equation by F
and then its an exact differential equation
do u know how to find the solution of an exact diff equation?

Answer 7

lalaly thanku thanku :) sister u rock :D

Answer 8

lol anytime:)