The number of phone calls that arrive at a phone exchange is often modeled as a poisson random variable. Suppose that on the average there are 24 calls per hour. What is the probability that there is no calls in 5 minutes?
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OpenStudy (wasiqss):
c on average there is 60/24 =2.5 calls per min
OpenStudy (anonymous):
how does that help me find the probability there are no calls in 5 minutes?
OpenStudy (wasiqss):
we must evaluate proability of getting a call every min
OpenStudy (wasiqss):
u can do that or i shud do
OpenStudy (anonymous):
you should probably haha
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OpenStudy (wasiqss):
y he deleted it :P
OpenStudy (anonymous):
i dont know!
OpenStudy (wasiqss):
now its easy
OpenStudy (wasiqss):
24/60 = number of calls per minute
OpenStudy (wasiqss):
sorry i mis read it
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OpenStudy (wasiqss):
0.4 calls per min
OpenStudy (mathmagician):
made a mistake- during 5 minutes there will be (24/60)*5=2 calls, so \[\lambda=2\] and probability that there will be no calls is \[2^{0}*e ^{-2}/0!=0.135\]
OpenStudy (anonymous):
Great, Thanks! Could you answer my other guestion mathmagician?