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solve the following inequality 9x-80>9/x
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x>9
oh hold the phone missing a piece
need to solve \[9x-80>\frac{9}{x}\] \[9x-80-\frac{9}{x}>0\] \[\frac{(x-9)(9x+1)}{x}>0\] critical points are at -1/9, 0, 9
solution is \[-\frac{1}{9}<x<0, x>9\] two intevals
@Luis Rivera you cannot multiply by x, because you do not know whether x is positive or negative
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so you don't know whether to keep the inequality or switch it. you have to put everything on one side of the inequality and make it > 0
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