integral using partial fractions(2x+4)/x^3-2x^2 dx

Question

anonymous · Answer

$$\int\limits_{}^{} 2x+4\div \sqrt{x ^{3}-2x ^{2}}dx$$

anonymous · Answer

the square root isnt in the problem im sorry i looked at the wrong problem

anonymous · Answer

Split into 2 parts first!

anonymous · Answer

thats what i was thinking

anonymous · Answer

Did you see x canceled out in the first part?

anonymous · Answer

nah i think splits up in to 3 parts and the last one you use long divsion to solve

anonymous · Answer

but im not sure im just trying to match it up to an example i had

anonymous · Answer

We're not in the same pace!
I'm talking about split the upper! then from the second part we split the lower into 3 parts.

anonymous · Answer

The one split in 3 parts apply partial fractions technique!

anonymous · Answer

It's fine that you just go straight split the lower into 3 parts!

anonymous · Answer

2x + 4 = A/x + B/x² + C/ ( x -2)

anonymous · Answer

Denominator = x² ( x-2)

anonymous · Answer

would it come out to be $$2x+4/x -\ln \left| x \right|+2\ln \left[ x-1 \right]+C$$

anonymous · Answer

Let me check!

anonymous · Answer

= 2 ln|x| + 2/x - 2ln|x-2| + C

anonymous · Answer

So, you're okie with the result?

anonymous · Answer

i was off how did i  mess up my numbers?

anonymous · Answer

Just take time to familiarize your self with the form!

anonymous · Answer

yeah ill look over it again
thanks!

anonymous · Answer

practice makes perfect :)