Question

(logs) find the solution:10^(x+3)=6^(x)

Answer 1

start with
\[(x+3)\ln(10)=x\ln(6)\] and then do some algebra to solve for x

Answer 2

i need help with doing the rest, i know how to do that but then i get lost

Answer 3

oh ok

Answer 4

\[\ln(10)x+3\ln(10)=\ln(6)x\]
\[\ln(10)x-\ln(6)x=-3\ln(10)\]
\[x(\ln(10)-\ln(6))=-3\ln(10)\]
\[x=\frac{-3\ln(10)}{\ln(10)-\ln(6)}\]

Answer 5

don't forget that
\[\ln(10)\] and
\[\ln(6)\] are just some numbers, treat them as constants

Answer 6

i really dont get it:/

Answer 7

can you explain it to me please