Question

find the solution of the equation:
2ln(2+x)=1

Answer 1

\[2\ln (x+1)=1\]\[\ln (2+x)=1/2\] \[e ^{\ln (2+x)}=e ^{(1/2)}\] \[2+x=e ^{(1/2)}\]\[x=(e ^{(1/2)})/2\]

Answer 2

Actually,
x = e^(1/2) - 2 = -.35

Answer 3

Should be

\[x=e ^{(1/2)}-2\]

Answer 4

I saw it right after I posted.

Answer 5

okay thank you so much

Answer 6

you're welcome