what is the nth term of the sequence 1,-2/3,4/9,-8/27

Question

anonymous · Answer

(2-n)(-2/3)

-4+n/3

anonymous · Answer

^ that doesn't make sense... ignore that

anonymous · Answer

lol

anonymous · Answer

its basically asking what is the formula

anonymous · Answer

I get the pattern.. the difficult part is writing the formula... yup.

anonymous · Answer

n(-2/3)+(2/3)

It's almost there... uggh... this is annoying me

anonymous · Answer

they are fractions btw

anonymous · Answer

Yeah.. I figure hahah

anonymous · Answer

figured*

anonymous · Answer

lol sorry

anonymous · Answer

it's okay... I just feel like murdering this problem.. ya know if that's physically possible. :P

anonymous · Answer

i know same here...ive been trying for so long

anonymous · Answer

(-2^n-1)/(3^n-1)

n=1... 1
n=2...-2/3
n=3...4/9
n=4...-8/27

OMG I FIGURED IT OUT!! :D

anonymous · Answer

$$-2^{n-1}/3^{n-1}$$

campbell_st · Answer

the common ratio is -2/3 and a = 1   the series in geometric

then 
$$T _{n} = 1\times(-2/3)^{n-1}$$

anonymous · Answer

^ do you really the need the one there?

anonymous · Answer

either way.. both equations work!! ^.^ and now I'm really happy because I get it! :D

campbell_st · Answer

well the general term in any geometric sequence is

$$T _{n} = ar^{n-1}$$

anonymous · Answer

thank you both so much, great help