$$(1+xy)y dx + x(1-xy)dy = 0$$
Get the general solution.

Question

$$(1+xy)y dx + x(1-xy)dy = 0$$
Get the general solution.

anonymous · Answer

Hello Guest, I hope you won't leave me (:forever alone:)... and then finally maybe somehow post the solution.

anonymous · Answer

the IF is 1/(2x^2y^2) 
after multiplying with IF one get ((1/2x^2y) +1/(2x))dx +((1/2xy^2) -1/(2y))dy =0
thus the equation becomes exact
now after integ 
we have
-1/(2xy) +1/2 lnx -1/2 lny = c (u can adjust c as per req)
hope this solves ur problem
suggest if i am not correct

anonymous · Answer

You are right, thanks! :-)

anonymous · Answer

may i know which book ur following for ur grads

anonymous · Answer

I am just a high school graduate. The book I am following is, http://www.tatamcgrawhill.com/html/9780070080805.html Preview: http://books.google.co.in/books?id=yYOShDcOfkkC&pg=PR6&dq=vikas+rahi+calculus+ebook&hl=en&sa=X&ei=_Y1dT_79MMKxrAf5-8GaDA&ved=0CEkQ6AEwAQ#v=onepage&q=vikas%20rahi%20calculus%20ebook&f=false