Question

Need help squaring these..
___ ______
√x-2 -1 = √2(x-3)

Answer 1

\[\sqrt{x-2}-1=\sqrt{2(x-3)}\]
\[(\sqrt{x-2}-1)^2=(\sqrt{2(x-3)})^{2}\]

Answer 2

\[x-1-2\sqrt{x-2}=2(x-3)\]

Answer 3

x-1-2√(x-2)=2(x-3)

x-1-2√(x-2)=2x-6

-2√(x-2)=x-5

√(x-2)=(-x+5)/(2)

(√(x-2))^(2)=((-x+5)/(2))^(2)

x-2=((-x+5)^2)/(2)^2

x-2=((-x+5)^(2)) / 4

4x-8=(-x+5)^2

4x-8-(x^(2)-10x+25)=0

4x-8-x^(2)+10x-25=0

14x-33-x^2=0

-x^2+14x-33=0

x^(2)-14x+33=0

(x-3)(x-11)=0

x=3,11
The solution 11 is not valid,
x=3

Answer 4

awesome thank you.... the square was throwing me off...