Question

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

Answer 1

http://answers.yahoo.com/question/index?qid=20100722225418AAW0zGP

Answer 2

Equation of a straight line: y = mx + c
Where m is the gradient
2 lines are parallel when the gradient of them both is equal
so as long as you have y = -3x then you can put any number after it
and the new line would be Parallell
e.g.
y = -3x + 56434657567099123
y = -3x + 1

For it to pass through ( -1 , 6 ) then put the numbers in and see what you get ( but dont change the gradient )
e.g.
y = -3x + 3 ( when x = -1 , y = 6 )

Answer 3

Well, parallel lines have the same slope (m) and a different y-intercept (b).
Slope intercept form is y=mx+b
Your original equation is y = -3x + 12.
-3 is the slope, and 12 is the y-intercept.
To find the y-intercept of the parallel line, we take the coordinates (-1, 6) and plug them into the equation y= -3x+b.
It looks like this 6= -3(-1)+b.
Solve for b.
6= -3(-1)+b
6= 3+b
3= b

So your parallel line equation is y= -3x+3.

Answer 4

wow @Steph_Rawr352 nice comeback lol

Answer 5

lol

Answer 6

let the equation of required line is m.since this is parallel to the given line hence both has same slope i.e m=-3.
hence the equation of required line will be
(Y-6)=-3(X-(-1))=>Y=-3X-3+6=>Y=-3X+3...

Answer 7

LOl thanks to everybody