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y = (e^x + 10)/(e^x - 10). Find (dy)/(dx) im confused w/ the quotient rule
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heres what i have found
(e^x+10)1-(e^x+10)(1)/(e^x-10)^2
is that right so far?
no
quotient rule of f(x)/g(x) is [g(x)*f'(x)-f(x)*g'(x)]/g^2(x)
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i know (g(x)f^'(x)-f(x)g^'(x))/([g(x)]^2).
dy/dx of (e^x+10) is not 1
e^x =1 right and the deriv of 10 =0
no e^x = e^x
i thought e^x was number
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it is but you are differentiating x not e
so its (e^x+10)(e^x)-(e^x+10)(e^x)/(e^x-10)^2
the left side the first term is e^x-10
ok how do i reduce it?
factoring out what?
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just multiply through and see is anything drops out
i dont factor out e^x?
why would you it doesnt help reduce it any
oh ok i got it
it is (e^x)(-20)/(e^x-10)^2
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yes it is, great work
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