Question

Let f(x) = n^2 + 2n + 4 and g(x) = -3n + 2 find (g of f)(1)

Answer 1

actually first you need
\[f(1)\]

Answer 2

\[f(1)=1+2+4=7\] and your last job is to find
\[g(7)\]

Answer 3

-19?

Answer 4

yes

Answer 5

Or do the whole thing in one bunch
gf(1)
g(f(1))
g(n^2 + 2n + 4 )
-3(n^2 + 2n + 4 ) + 2