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Let f(x) = n^2 + 2n + 4 and g(x) = -3n + 2 find (g of f)(1)
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actually first you need \[f(1)\]
\[f(1)=1+2+4=7\] and your last job is to find \[g(7)\]
-19?
yes
Or do the whole thing in one bunch gf(1) g(f(1)) g(n^2 + 2n + 4 ) -3(n^2 + 2n + 4 ) + 2
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