Question

the length of a rectangle is increasing at the rate of 2 m/s, while the width is increasing at a rate of 1 m/s. When the length is 5 m and the width is 3 m how fast is the area increasing?

Answer 1

RELATED RATES

Answer 2

A = l*w
dl/dt = 2
dw/dt = 1
l=5
w=3
dA/dt - ?

Answer 3

dA/dt = l*dw/dt + w*dl/dt = 5*1+3*2 = 5+6 = 11

Answer 4

given dl/dt=2m/s
dw/dt=1m/s
A=L*W
da/dt=ldw/dt+wdl/dt
=5*1+3*2=5+6=11
da/dt=11m/s