given the points (2,-1,3) and (1,4,-3) what will be the vector? should I solve it with vector= (x2-x1, y2-y1, z2-z1)
yes
(2,-1,3) - (1,4,-3) ---------- works too
but at http://tutorial.math.lamar.edu/Classes/CalcII/EqnsOfLines.aspx in example 1 the author has taken found the vector v totally differently
according to him the vector = <1,-5, 6>
you asked should you, not; how many ways are there to acheive the same thing tho
"proper" vectors begin with a positive x component
if the direction is given, then by all means; end - start = vector
but between 2 random points its usually "proper" to deign it with a positive x component
I didn't get you
<-1,5,-6> is not proper vector writing ..... x is a negative number <1,-5,6> is "proper"
so if two points are given then we will have to consider the lower value of x as x1 and the bigger value of x as x2?
if the question asks; what IS the vector from A to B; then you MUST do B-A to get the vector
why not? I mean we can draw it in three dimension, isn't?
OK if he says through points A and B then we will have to use the logic and for our own ease we will pick the bigger valued x as x2
am I right?
|dw:1331746660733:dw| this is FROM A ... TO B but if no direction is stated then you pick the vector notation such that x is positive
@mattfuery we can get more work accomplished of the site doesnt freeze up on posting :/
@mattfeury and get an easier name to spell please :)
sorry, who is mattfeury?
hes a programmer for the site along with @shadowfiend and others, they run the site like @darthsid
the @ sign pings them to see if theyll come fix stuff .... hopefully :)
ok
So please tell me am I right what I said above?
but yes, if they just ask for a vector between A and B, just subtract one point from the other; and if x is negative; swap out all the signs
gr8 thanks a tonne bro
<-1,5,-6> is not "proper" notation for a vector between A and B <1,-5,6> IS the proper notation
thanks bro
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