Determine the 2 numbers whose difference is 12 and whose product is a maximum.I came up with (x + 6)^2 - 36 But, what do I do now? It is functions, grade 11. Do I need to explain how I got x + 6)^2 - 36?
well, how DID you come up with it?
x+y = 12 ; y = 12-x xy = max x(12-x) = max 12x - x^2 = max at its vertex
whose difference is 12 ... i gotta get better glasses
x-y = 12 ; y = x-12 xy = max x(x-12) = max x^2 - 12x = max at infinity
i repeat, maybe it means two numbers whose sum is 12 if the difference is 12 i can make it as large as possible
100,112 100000, 100012 etc
id do sum too :)
I have no idea!
i am going to bet it means two numbers that add to 12 not "whose difference is 12"
the answer is (0,9) it's at the back of the book, but how????
9*0 = 0 not 12
ok now we really have a problem because it is not the case that the difference or the sum of 0 and 9 is 12!!
theres a valid thought in there someplace lol
either there was a typo in the book or this is the answer to a different problem 0 + 9 = 9, 9 - 0 = 9, there is no 12 to be had here
I'm sorry, it's a wrong question the answer is + and - 6
produce is a minimum maybe ??
Itr makes sence now, but in my formula it is just 6, where do we get the - 6?
nope, says max
now way that \[6\times -6=- 36\] is a maximum
#no way
but even if it say minimum ( there is similar question in the book but with min), how the heck we will get -6 and +6?
what about 100 and 112 the difference is 6 and the product is much bigger than -36
This question drives me nuts lol
i can see why because it makes no sense at all
minimum represents the direction of the porabola ( opens up )
we don't really care about it
we can solve this problem find two numbers whose sum is 12 and whose product is a maximum
I don't knwo....
sorry
That's fine. I'll ask the teacher
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