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Mathematics 11 Online
OpenStudy (anonymous):

Solve each equation

OpenStudy (anonymous):

\[6^{x} = 444\]

OpenStudy (anonymous):

\[4\log_{3} 2x - 2\log_{3} x = 1\]

OpenStudy (anonymous):

log(5x - 4 ) = 3

OpenStudy (radar):

\[6^{x}=444\] x log6=log444 x=log444/log6 x=3.4021444667 using calculator. Did you follow with understanding?

OpenStudy (radar):

Do you have an \[x ^{y}\] function key on your calculator, you then can check it.

OpenStudy (radar):

\[6^{3.402144466}=444\]

OpenStudy (radar):

I won't go any further until you understand this one, monologs are no fun.

OpenStudy (radar):

For my own curiosity, is the third one (last) logs to the base 2???\[\log _{2}(5x-4)=3\]

OpenStudy (anonymous):

no it's base 10

OpenStudy (radar):

Hmmmmm I cannot come up with their answer to the last one, I will be thinking bout that one while you try and understand the answer to the first one.

OpenStudy (radar):

O.K I got it for the last one. Let me know if you followed the first one with understanding.

OpenStudy (anonymous):

i understand the first one, you divided the logs to get x

OpenStudy (radar):

Yes, and a hint for the last one. Log(5x-4)=3 antilog 3 = 1000

OpenStudy (radar):

\[4\log _{3}2x-2\log _{3}x=1\] \[(2x)^{2}/x ^{2}=1\] \[((16x ^{4})/(x ^{2}))=1\] \[16x ^{2}=1\] \[x ^{2}=1/16\] \[x=\sqrt{1/16}=\pm1/4\]

OpenStudy (radar):

*That 2nd line should be\[(2x)^{4}/x ^{2}=1\]

OpenStudy (radar):

typo u know

OpenStudy (anonymous):

thanks a ton!

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