how do i integrate ucos(u)?
i dont know how to integrate anything which is timed together, how do I? I haven't done anything to do with int by parts yet
can i just do the integral of the u and the integral of the cos(u) and times them together?
integration by parts do you know it?
no, doing it next lesson
so i don't need it for this homework that I am doing
and by the way\[\int f(x)g(x)dx\neq\int f(x)dx\cdot\int g(x)dx\]that is a criticalo thing to know
critical*
aaaawwww :(, thats simple though lol
but then we would never need u-substitutions now would we? ;)
life would be so mch easier for me if there was no need for the u substitutions at the moment lol
can the question be done without int by parts then?
the start question was integrate xcos(x^2) using the substitution u=u^2
I'm going to say no, though I have been known to be wrong once or twice :)
-but the integral you just wrote can be done without integration by parts
you have the wrong u-sub\[\int x\cos(x^2)dx\]\[u=x^2\]so what is du ?
2x(dx)?
right, so what is our integral now?
how about if I write it like this?\[\int x\cos(x^2)dx=\int\cos(x^2)(xdx)\]then we have\[u=x^2\implies du=2xdx\]so we are going to sub\[xdx=\frac12du\]
\[1/2\int\limits_{}^{}\cos(x^{2}) .du\]?
almost, but you forgot to sub u=x^2
1/2 int cos(u) .du
there we go :)
:)
therefore, the answer is: 1/2sin(x^2) ?
don't forget +C but, yes
i always forget the constant lol :)
thank you so much for your help, you have been insanely helpful :D
the funny thing is you pretty much don't need it until you take differential equations, at which point it is essential you are welcome, see you around :D
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