Question

i need help with trig identities,

sec(feta)-cos(feta)=sin(feta)tan(feta)

Answer 1

theta*

Answer 2

lol thanks :)

Answer 3

go to patrickjmt.com he has a lot of helpful tutorials from algebra to linear algebra and everything in between including trig

Answer 4

i think those videos would help you understand better than on here

Answer 5

:D thanks i will check him out! i watched him for a geometry thing i had to learn. he is great. so what "skills" would you need from algebra to solve trig identities?

Answer 6

just basic HS algebra

Answer 7

Are you looking to prove this identity?

Answer 8

yes @ChrisS

@Eherre1989 thanks! i will check into that! my trig teacher is fresh out of college :/ so it sucks

Answer 9

my trig is pretty rusty, but as Eherre is saying some algebra will be helpful for this, also remembering how trig functions translate between eachother is helpful... for instance sec = 1/cos

I have to step away for a second, but I'll be happy to try to work through this proof myself and help you understand it as soon as I do, but I may not be the fastest... I'm kinda multitasking at the moment :P

Answer 10

\[\sec \theta-\cos \theta=\sin \theta \tan \theta\]
\[\frac{1}{\cos \theta}-\cos \theta=\sin \theta \tan \theta\]
\[\frac{1-\cos ^{2}\theta}{\cos \theta}\sin \theta \tan \theta\]
\[\frac{\sin ^{2}\theta}{\cos \theta}=\sin \theta \tan \theta\]
\[\frac{\sin \theta}{\cos \theta}\times \sin \theta=\sin \theta \tan \theta\]
\[\tan \theta \sin \theta=\sin \theta \tan \theta\]

Answer 11

there ya go... I knew someone would come along and get it faster than me lol.