haloke does 176 joules of work lifting himself 0.300 meters. what is haloke's mass?

Question

haloke does 176 joules of work lifting himself 0.300 meters.  what is haloke's mass?

anonymous · Answer

The minimum force that Haloke must exert on himself to lift himself is equal to his weight.

If he has mass m, then his weight will be: $$F_{g}=mg$$If he lifts himself a distance d, then the work he does is:$$W=Fd \sin \theta=F_{g}d=mgd$$It is given that W=176 J and d = 0.3 meters; g = 9.81 m/s^2.
Now you can solve for m.

ALTERNATE SOLUTION:

The work done is equal in magnitude to the change in potential energy (assuming no energy is lost). Thus: $$W=\Delta PE = mg \Delta h$$Again, you are given the values for W and h, so you can easily find the mass.

anonymous · Answer

BY THE CONSERVATION OF ENERGY:
                                                 WORKDONE=CHANGE IN POTENTIAL ENERGY
                                                           176        =Uf-Ui
                                                          176=mgh 
                                                           m=176/(10*.3)=58.66kg