What mass in grams of sodium nitrate, NANO3, is produced if 20.0g of sodium azide, NaN3, in a dilute aqueous solution are reacted with excess silver nitrate, AgNO3, according to the following chemical equation?

NaN3(aq) + AgNO3(aq) -- AgN3(s) + NaNO3(aq)

Question

What mass in grams of sodium nitrate, NANO3, is produced if 20.0g of sodium azide, NaN3, in a dilute aqueous solution are reacted with excess silver nitrate, AgNO3, according to the following chemical equation?

NaN3(aq) + AgNO3(aq) --> AgN3(s) + NaNO3(aq)

xishem · Answer

Well, we start by converting mass of sodium azide to amount:$$20.0g\ NaN_3*(\frac{1mol\ NaN_3}{65.010g\ NaN_3})=0.308mol\ NaN_3$$Then convert this amount to amount of sodium nitrate using a mole factor conversion:$$0.308mol\ NaN_3*(\frac{1mol\ NaNO_3}{1mol\ NaN_3})=0.308mol\ NaNO_3$$Then, finally to a mass of sodium nitrate:$$0.308mol\ NaNO_3*(\frac{84.995g\ NaNO_3}{1mol\ NaNO_3})=26.1g\ NaNO_3$$

anonymous · Answer

Which of the following is a balanced equation for Copper (II) sulfate + aluminum --> aluminum sulfate+solid copper?
A. CuSO4(aq)+Al(s) --> Al2(SO4)3(aq)+Cu(s)
B. 3 CuSO4(aq)+2Al(s) -->Al2(SO4)3(aq)+Cu(s)
C. 3 CuSO4(aw)+2Al(s) --> Al2(SO4)3(aq) +H(g)

anonymous · Answer

can someone help me

jfraser · Answer

none of the choices are correctly balanced, but the closest option is B