Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Observe the composite figure below. The bottom shape is a cube with base edges of 16 meters. The top shape is a right pyramid with a height of 15 meters. What is the surface area of this composite figure? Answer 544 m2 1,280 m2 1,824 m2 2,080 m2

OpenStudy (anonymous):

OpenStudy (darthsid):

What's your working so far? How are you approaching this?

OpenStudy (anonymous):

i have made it absolutely no where on this problem.

OpenStudy (darthsid):

Do you know what the area of a square is?

OpenStudy (anonymous):

yesss

OpenStudy (darthsid):

Great! So try to divide the figure into two parts: 1. the pyramid 2. The cube

OpenStudy (darthsid):

Now, a cube's surface is basically 6 squares, so what would the area of the surface of the cube be?

OpenStudy (anonymous):

256???

OpenStudy (darthsid):

That's the area of one square. A cube's surface is made of 6 squares. So the surface area of the cube is 6 times the area of a square, right?

OpenStudy (anonymous):

so that would be 1,536

OpenStudy (darthsid):

Yeah, so that's the surface area of the bottom part. Now let us look at the top part, it is a right pyramid, which is basically 4 triangles and a square on the surface

OpenStudy (darthsid):

DO you have the formula for the surface area of a right pyramid?

OpenStudy (anonymous):

B+ 1/2ps?

OpenStudy (anonymous):

yes

OpenStudy (darthsid):

Exactly, for the pyramid your main problem is finding s what's the formula for s? You're very close!

OpenStudy (anonymous):

i have no idea ! haha

OpenStudy (darthsid):

B is the area of the base, which is a square, which you calculated above was 256! P is the perimeter of the base, which is the sum of all sides of the base, So P = 16 + 16 + 16 + 16 = 64

OpenStudy (darthsid):

So we are left with s, which is the slant height. Slant height \[s=\sqrt{{h^2}+{r^2}}\] where h is the height, and r is the radius of the base The radius of the base is half the side of the square, so r = 8. Can you calculate s?

OpenStudy (anonymous):

289?

OpenStudy (anonymous):

17

OpenStudy (anonymous):

nno 288

OpenStudy (anonymous):

16

OpenStudy (darthsid):

No no, square root that! You are on the right track tahtah99 :)

OpenStudy (darthsid):

yess, 17!

OpenStudy (darthsid):

So, you said the formula was B + 1/2Ps B = 256 (area of square) P = 64 (perimeter of square) s = 17 So total surface area of the pyramid is?

OpenStudy (anonymous):

800 ?

OpenStudy (darthsid):

Great! That's correct.

OpenStudy (anonymous):

see i told you!!

OpenStudy (anonymous):

you got it!!

OpenStudy (anonymous):

-_____- hahah

OpenStudy (darthsid):

So now, you have a pyramid and a cube Area of pyramid = 800 Area of cube = 1536 Now if you join the two, you will not see one side of the cube, and the base of the pyramid. Do you understand that?

OpenStudy (darthsid):

It's not done yet :D

OpenStudy (anonymous):

dont celebrate, its not done yet!!

OpenStudy (anonymous):

oh Lord.. yeah i understand

OpenStudy (darthsid):

So you have to subtract the area of two things: 1. The base of the pyramid 2. One square from the cube.

OpenStudy (anonymous):

so subtract 512?

OpenStudy (darthsid):

So your final area will be: 1536 + 800 - (area of 1 square) - (area of 1 square) = 1536 + 800 - 256 - 256

OpenStudy (darthsid):

Exactly! You got this!

OpenStudy (anonymous):

exactly!! WHAT I SAY?? YOU GOT IT!

OpenStudy (anonymous):

is the answer c?

OpenStudy (anonymous):

THATS WHAT IVE BEEN TRYING TO SAY!! YES IT IS!!!!!!

OpenStudy (darthsid):

Yes it is!

OpenStudy (darthsid):

Congrats :)

OpenStudy (anonymous):

thank you so much ! : )

OpenStudy (anonymous):

SEE! NOOOOOWWW YOU CELEBRATE!!

OpenStudy (anonymous):

YOUR VERY WELCOME~!

OpenStudy (anonymous):

hahahahahahha

OpenStudy (darthsid):

Glad to help!

OpenStudy (anonymous):

glad to help too!

OpenStudy (anonymous):

could you check my answer for the last question ?

OpenStudy (anonymous):

nvm got it

OpenStudy (anonymous):

ok.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!