3log(base5)y - log(base y)5 = 2?
Thanks in advance!

D: Can somebody deliver a similar eq'n and how to solve?

Question

3log(base5)y - log(base y)5 = 2?
Thanks in advance! 

D: Can somebody deliver a similar eq'n and how to solve?

anonymous · Answer

$$3 \log_{5} y - \log_y 5 = 2$$

anonymous · Answer

According to the q'n book, the answer is supposed to be:
5 or 5^-1/3

anonymous · Answer

ok, let's try this...
see the logy 5?  can you see this change to 1/(log5 y)?

anonymous · Answer

so now your equation is:
3*log5 y - 1/(log5 y) = 2

anonymous · Answer

Oh. OH. :)) 
I didn't know that rule. I honestly didn't. Makes things easier, thank you very much! @dpaInc

anonymous · Answer

yea.  but I don't like to call it a rule... I just revert back to the definition of logs and try to get  all logs to the same base.

anonymous · Answer

so, are you good from here?  basically you'll get a quadratic in terms of log5 y... and you'll need to solve it...

anonymous · Answer

I think I'm good. :D I'd be able to solve it from here. 
Just started taking up Additional Mathematics, so I'm very new to all this... this. Haha. Thanks. @dpaInc

anonymous · Answer

glad to help... yw...