A golf ball is struck at ground level. The speed of the golf ball as a function of the time is shown in Figure 4-36, where t = 0 at the instant the ball is struck. The scaling on the vertical axis is set by va=16 m/s and vb=32 m/s. (a) How far does the golf ball travel horizontally before returning to ground level? (b) What is the maximum height above ground level attained by the ball?

Question

anonymous · Answer

attachment

anonymous · Answer

why do i get the feeling my question is avoided on purpose

.sam. · Answer

va and vb is the vertical velocity?

.sam. · Answer

nvm i thought so

.sam. · Answer

so, you need to calculate the time for the whole trip of the ball

.sam. · Answer

you know that when the ball reaches maximum height, the vertical velocity is 0

anonymous · Answer

sorry was away

anonymous · Answer

yep they are the velocity

.sam. · Answer

va shouldnt be 32 because the direction of velocity changes, va should be 0

.sam. · Answer

Do you have the answer with you?

anonymous · Answer

nope. not for this one hehe

anonymous · Answer

i guess it doesn't matter...you just do vb-va

.sam. · Answer

Or you could use$$x=\frac{v _{b}+v _{a}}{2}t$$

.sam. · Answer

so i should be 120m

.sam. · Answer

it*

anonymous · Answer

ahh k. but that is the initial velocity then. 16m/s

anonymous · Answer

hmm i thinking you have to square the two measurements then minus them then square root them...but still not sure