A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. After about how many seconds will the ball hit the ground?

Question

anonymous · Answer

$$-16t^2+60t+6=0$$ solve for t

anonymous · Answer

maybe easier to solve 
$$8t^2-30t-3=0$$ and the quadratic formula

tommo_lcfc · Answer

The ball hits the ground when h = 0.

0 = 16t^2 - 60t - 6

Use the quadratic formula to get

t = 8.96 or t = -5.21.

We reject the negative time because time cannot be negative!

So t = 8.96 to 2dp