Question

Suppose f(x)= ln3x and f^-1X denotes the inverse of f. Then the integral of f^-1x dx =

Answer 1

my work so far:
x= ln (3y)
e^x= 3y
y = E^x /3 (that would be e to the x, all divided by 3)
y= 1/3 e^x

this is where i get confused. i know the antiderivative of e^x is e^x, but i dont know how it works with a constant in front. my textbook isnt helping at all!