Question

solve 4^(x+7)=6^(x-1)

x ≈ 0.04

x ≈ 0.05

x ≈ 19.51

x ≈ 28.35

Answer 1

i got a but i think i am wrong

Answer 2

log both sides
use the log property to drop the exponents, then solve

Answer 3

i...iam ashamed to say i dont know how to do this

Answer 4

i think i did the whole thing wrong

Answer 5

ok I will help you, no shame at all.
give me a second to type it in

Answer 6

thank u

Answer 7

\[4^\left( x+7 \right)=6^\left( x-1 \right)\]
\[log 4^\left( x+7 \right)=log 6^\left( x-1 \right)\]

Answer 8

you can take the common log or natural log of both sides,
method does not matter

Answer 9

(x+7)log4=(x-1)log6
xlog4+7log4=xlog6-log6

Answer 10

o.o log is on the calculator but its not in the problem is it just assumed?

Answer 11

no we do not need that but you can use log in the calculator later to give us a number.
We are just doing algebra at this point

Answer 12

xlog4+7log4=xlog6-log6
xlog4-xlog6=-7log4-log6
x(log4-log6)=-7log4-log6
\[x=\frac{-7\log4-\log6}{\log4-\log6}\]
ok put that in your calculator, be careful because you will need many parenthesis

Answer 13

x is approximately 28.35218066

Answer 14

Let me check my solution to see that it works

Answer 15

ok :D

Answer 16

yes it works........ :)

Answer 17

Did you understand my steps?