an aircraft is about to take off from a runway which is 850m long its take off speed must be 90m.s calculate the minimum acceleration necessary for the aircraft to take off
We are given the distance the aircraft covers before it achieves a speed of 90m/s as 850 m Now initially velocity of the aircraft is u 0 m/s final velocity v= 90m/s distance s= 850 m/s a= acceleration? We'll use the relation \[v^2-u^=2as\] u=0 \[(90)^2=2 \times a \times 850\] Can you find acceleration now?
Sorry it's \[v^2-u^2=2as\]
Did you understand?
ya makes sense then you square root the answere right
No we need to find a!!! this does not require square rooting \[2as=v^2\] \[a=\frac{v^2}{2s} m/s^2\]
oh ya think i get it mind just checking my answer
Yeah, what do you get?
4.8 m/s
It's right but the unit of acceleration is m/s^2 so 4.8 m/s^2
yeah i know just couldn't figure out how to add superscripts but thanks a million man you were really helpful :D
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