Question

limx→π/4cos2x÷sinx−cosx

Answer 1

Is it as x approaches pi?

Answer 2

\[\lim_{x \rightarrow \pi} (4\cos 2x)\div(\sin x -\cos x)\]

Answer 3

probably he meant:
\[\lim_{x \rightarrow \pi/4}\]
Please confirm

Answer 4

True. Good call.

Answer 5

i am going to guess it is
\[\lim_{x \to \frac{\pi}{4}}\frac{\cos(2x)}{\sin(x)-\cos(x)}\]so you would get
\[\frac{0}{0}\] by substitution.

Answer 6

but it looks like it is a one step l'hopital problem if that is the question

Answer 7

\[\lim_{x\to \frac{\pi}{4}}\frac{2\sin(2x)}{\cos(x)+\sin(x)}\] and done