Question

Please transform the polar equation to an equation in rectangular coordinates.

rcsc(theta)=3

Answer 1

\[(x-3/2)^{2}+y ^{2}=(3/2)^{2}\]

correct?

Answer 2

Anyone?

: )

Answer 3

r csc(a) = 3
r/sin(a) =3
use x= r*cos(a)
y= r*sin(a)
x^2+y^2= r^2

so how about this:
\[ \frac{r}{r}\cdot \frac{r}{sin(a)}= 3\]
\[ \frac{x^2+y^2}{y}=3 \]

Answer 4

we can simplify by completing the square (for y), to find the equation of a circle.

Answer 5

@mikejano, sorry... got called out...
yes. your answer is good...

Answer 6

no, the center of the circle is at (0,3/2) ( not (3/2,0) )

Answer 7

yes, phi is correct.