Using synthetic division, what is the quotient: (y3 + 6y2 + 10y + 3) ÷ (y + 3) ?
So again we do the same set up for the last question you asked... y+3=0 when y=-3 -3| 1 6 10 3 <----coefficients of the terms on top | =================== ^ | bottom's zero
3| 1 6 10 3 | =================== First Step: Bring down that 1 3| 1 6 10 3 | =================== 1 Second Step: Multiply 3 and 1 That result goes under the 6 like so: 3| 1 6 10 3 | 3 =================== 1 Third Step: Add the 6 and 3 3| 1 6 10 3 | 3 =================== 1 9 Fourth Step: Multiply that 9 and that 3 on the outside (the bottom's zero) 3| 1 6 10 3 | 3 27 =================== 1 9
What is the next step? What is your guess on the next step?
ummm idk
im having trouble what would be the answer to make sure im right
Sorry I had a quick think to do I don't know the answer until I have worked it out so lets do it together
@KingJ So just like we added the 6 and 3 We need to also add the 10 and 27
3| 1 6 10 3 | 3 27 =================== 1 9 37 So you can think of it like this the numbers in vertical formation add those The numbers at sorta a diagonal you multiply those like So we do 3 times 37 to figure out what goes underneath the last coefficient (the 3)
Since 3(37)= 111 we have 3| 1 6 10 3 | 3 27 111 =================== 1 9 37 | <----This last number will be our Remainder
What is the remainder?
What operation do we perform on the 3 and 111?
The numbers are vertical and I said the operation you perform is....?
you add the 3 and 111
:) Right! Perfect!
3| 1 6 10 3 | 3 27 111 =================== 1 9 37 | 114 Ok so we have 1x^2+9x+37+114/(y+3)
so we divide n i should have my answer
We are done
We already divided
so the answer would be y2+3y+1
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