Question

log-5x=log(10-3x)

Answer 1

so:
-5x=10-3x
think about it, if the two members are equal the log will be the same ;)

Answer 2

thanks that was very helpful

Answer 3

Another path you can perform is use both member as exponent of your logarithm base, and log will disappear!(because log return an exponent, so, if you elevate the base with it it will return your argument ;))

Answer 4

@Louis, you can't do this, maybe you mean: log(-5x)=log(10-3x) => -5x=ilog(log(10-3x)) where ilog is the inverse logarithm function (aka b^x, with generic base b)

Answer 5

? You can't just move the log function! xD

Answer 6

\[-4_{3}-9m=-4\]
How about this question?

Answer 7

you mean 43?

Answer 8

or 4 in 3 base?

Answer 9

oh no sorry i meant\[-4\log _{3}-9m=-4\]

Answer 10

This pic have nosense here, -5 is negative and these formulas are useless for the solution of the problem

Answer 11

@tronlegacy use both members as power of 3 before you move your -4, so:
-4*log3(-9m)=-4 => log3(-9m)=1 => elevate => 3^(log3(-9m))=3^1 => -9m=3 ;)

Answer 12

@Luis Rivera and you find the solution ;) I think tronlegacy is smart enough to solve a first degrees equation XD