Question

Find the standard form of -x^2-4x+3

Answer 1

I can do positive one but not negative ones it's my first... do I just multiply by -1? no right?

Answer 2

What is the standard form of a quadratic?

Answer 3

i do believe it is "Ax^2 + Bx + C"

Answer 4

No, it's a(x-h)^2+k

Answer 5

What you said is general form... see from standard form you can easily find the vertex line of symmetry and minimum or maximum value

Answer 6

ahh, okay. i know that form as vertex form. :o

Answer 7

Oh, where are you from... lol nvm doesn't matter I really need help with this >.<

Answer 8

in the US...

Okay, so
y = -x^2 - 4x + 3
We'd factor out a -1 from the first two terms
y = -(x^2 + 4x) + 3
We want to complete the square for -( (x^2 + 4x + __) - ___ )

Answer 9

to complete the square, we'd just divide the 4 coefficient on the x by 2 and then square the value.

y = -( (x^2 + 4x + (4/2)^2) - (4/2)^2 ) + 3
= -((x^2 + 4x + 4 - 4) + 3
= -((x+2)^2 - 4) + 3 distribute the -1 back in
= -(x+2)^2 + 4 + 3
= -(x+2)^2 + 7

Answer 10

I'm an idiot!!! Why didn't I just take the negative out! Thank you very much man you saved my life I got kicked out of my schools basketball team because I was messing up... time to come back!

Answer 11

no problem! and good luck. :D
most things in algebra have the same process needed to figure similar problems out, i think