The following density function describes a random variable X.
f(x)=x/81 if 0
The graph of f consists of a line segment from (0,0) to (9, 1/9) and a line segment from (9, 1/9) to (18, 0) A) Draw in vertical line segments at x = 1 and x = 8 that extend from the x-axis to the graph of f. The area under the graph of f, above the x-axis, and between these two vertical segments is the probability that x lies between 1 and 8. This region is a trapezoid with height (8-1) = 7 and bases of length (1/81) and (8/81). The area of a trapezoid is ½h(b1 + b2) so the probability is ½(7)(9/81) = 7/9. If you've had integral calculus, it is 8 ∫ (x/81) dx 1 For (B), do the same process. You'll need to divide the region up into two trapezoids sharing a base at x = 9. Again, if you've had integral calculus the probability is given by 9................13 ∫ (x/81) dx + ∫ [(18 - x)/81] dx 6..................9..
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