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derivative y=(x+3)^3/x*sqrt(x)
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rewrite the denominator in index form as x^3/2 u - (x+3)^3 dv/dx= 3(x+3)^2 v = x^3/2 dv/dx = 3/2x^1/2 \[dy/dx = (x^{3/2} \times 3(x+1)^2 - (x + 3)^3 \times 3/2x^{1/2})/(x^{3/2})^2\] I'll let you simplify it
please help me. i have no idea,how to do it :)
just find common factors
can you explane how to know which function to use in eacht case,to get a right answer?
the quotient rule is in the form y = u/v then its a case of dy/xd = (vu' - uv')/v^2
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thanx !
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