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derivative y=In^4(8x-x^3)
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what grade r u in?
first
-_- we mean
can u give me a medal
@Suzan987654321 at least you should help aga solve the problem before you ask for medal?
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u right callisto! :)
is the expression \[y = \ln^{4}(8x-x^3)\]?
is this a final answer?
no i'm asking is that the expression of the question
oohh sorry,yest thats the one
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\[dy/dx =d/dx [\ln^{4}(8x-x^3)]\]\[ =d/dx [\ln(8x-x^3)]^4\]\[ = 4[ln(8x-x^3)]^3[1/(8x-x^3)](8-2x^2) \]\[ = 4(8-2x^2)[ln(8x-x^3)]^3/(8x-x^3)\]\[ = 8(4-x^2)[ln(8x-x^3)]^3/(8x-x^3)\]
thanx,can u please explane how did u get this one 4[ln(8x−x3)]3[1/(8x−x3)](8−2x2)
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