A car travels around a horizontal circular track at a constant speed of 58 km/h. If the radius of the track is 43 metres, what is the magnitude of the cars acceleration in m/s2?

Question

anonymous · Answer

a=v^2 /r
plug the values??

anonymous · Answer

the formula is 

a=v^2/r

so by subtituting the values
a=(58)^2/43

a= 78.23m/s^2

anonymous · Answer

the answer which the book gives is 6.0m/s^2 and i dont know how to get this value.

anonymous · Answer

@sgholap you forgot to convert velocity to m/s

anonymous · Answer

@michael  convert velocity into m/s and the plug the values!!!
you are sure to get it??

anonymous · Answer

ohhh!!!! i am really sorry michael i forget to convert it just do wat sarkar said will get the answer right