Is f(x) = √(x-3)^2+3 a function? If so, how do I know its domain and range?
\[f(x) = \sqrt{(x-3)^{2}+3}\]
I don't get it D:
in this question the domain is all real x. you want to avoid negatives in the square root. But given any number squared will result in a positive answer there are no restrictions on the domain. the range is what output do I get from the values of x that are input Since every input will result in a positive output and when x = 3 y = square root 3 the range is y>= square root 3
why would y me greater than or less than root 3?
the smallest y value occurs when (x - 3)^2 = 0.... and this is when x =3 the output will be square root 3
why will the output be square root of 3?
can you show me the whole calculation?
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