Question

Gaskin and sloan raced tpo the cotton patch. Gaskins speed was 12 kilometers per hour, while sloans was only 8 kilometers per hour. What was the time of each if gaskins time was 5 hours less than sloans time?

Answer 1

Let x = distance to cotton patch. Then solve: x/12 = x/8 -5

Answer 2

Gaskin and sloan raced tpo the cotton patch.

so this is linear in nature

Gaskins speed was 12 kilometers per hour, while
sloans was only 8 kilometers per hour.

What was the time of each if
gaskins time was 5 hours less than sloans time?

Answer 3

somebody give me an equation

Answer 4

an equation is something we have to build from the information given ....

Answer 5

ik

Answer 6

so, distance remains the same in each case since the cotton field hasnt moved

Answer 7

d = speed.g*time.g

d = speed.s*time.s

are how we should relate this things

Answer 8

speed.g = 12 ; speed.s=8

d = 12*time.g

d = 8*time.s

time.g = time.s-5


d = 12*(time.s-5)

d = 8*time.s


since d=d we equate the 2 to find the time for sloan

Answer 9

ummm could u put it in an equation?
like the full one

Answer 10

there are a myriad of different ways to solve this; im not sure which "equation" you are suggesting.

Answer 11

just one that gets the answers

Answer 12

well, if we equate the ds .... since d=d

d = d
12(s-5) = 8(s)

Answer 13

good is that the whole thing?

Answer 14

how would I know? I have to take a blind stab at this thing just to try to make sure im even answering the right question; much less try to determine what level of math you are trying to solve it in .....

but as is, you should be able to work out the time for sloan with that and compare it to gs time

Answer 15

its algebra 1

Answer 16

then yes, that should be the "whole thing" :)

Answer 17

ok
wait

Answer 18

solve it the way an algebra student would

Answer 19

can u solve it?

Answer 20

im done dude u can get off now