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d/dx(ln[e^(2(x)^1/2)cot^2((x)^1/2))
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My beautiful eyes!
lol,what?
\[\frac{d}{dx}\left(\ln\left(e^{2x^{\frac{1}{2}}}\cot^2\left(x^{\frac{1}{2}}\right)\right)\right)\]This?
|dw:1331932966529:dw|
the others are right
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simplify the problem using log laws \[\ln (e^{2\sqrt{x}}) + \ln (\cot^2(\sqrt{x}))\]
the 1st term becomes \[2x^{1/2}\]
yeah did that
why 2x^1/2? that's where am stock?
so the derivative is \[1/\sqrt{x}\]
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ok
the log of the exponential is just the power
you just need to find the derivative of the cot^2 stuff
yeah am getting this |dw:1331933273509:dw|
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