Question

y = ln( x^3 - 5 x + 13)

(dy)/(dx) =

Answer 1

use the chain rule

Answer 2

any help?

Answer 3

d/dx[ln y] = y'/y

Answer 4

another way of doing this is to let u = x^3 - 5x + 13
so y = ln u and

dy/du = 1/u and du/dx = 3x^2 - 5

so dy/dx = dy/du * du/dx = 1/u * 3x^2 - 5

= ( 3x^2 - 5) / (x^3 -5x + 13)

Answer 5

thanx