Solve 7 square root of 13 x end root minus 15 square root of 2 x end root plus 2 square root of 13 x end root minus 4 square root of 2 x
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OpenStudy (anonymous):
what's an end root?
OpenStudy (anonymous):
Just ignore the end part
OpenStudy (anonymous):
\[7\sqrt{13x}-15\sqrt{2x}+2\sqrt{13x}-4\sqrt{2x},\]\[9\sqrt{13x}-19\sqrt{2x}...\]and this is equal to?
OpenStudy (anonymous):
i guess just simplify?
OpenStudy (anonymous):
but you said solve, so is there an equation?
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OpenStudy (anonymous):
Yeah but I don't know how to do it. Do you just add/subtract like you would 2+2 or 2-2?
OpenStudy (anonymous):
just add/subtrac like terms...
OpenStudy (anonymous):
alright
OpenStudy (anonymous):
You can only do that to like-terms. For example, in your case,\[7\sqrt{13x}-15\sqrt{2x}+2\sqrt{13x}-4\sqrt{2x}\]is the same as\[\sqrt{13x}(7+2)+\sqrt{2x}(-15-4).\]Do you see this?
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
so that answer given by @pre-algebra in the last line is correct
OpenStudy (anonymous):
By the way, your problem cannot be simplified any further than\[\sqrt{x}(9\sqrt{13}-19\sqrt{2})\]