Question

if a=8, b=6, and c=6 then what are the angles of A,B,and C in degrees?

Answer 1

use cosine rule,cosA=(b^2+c^2-a^2)/2bc

Answer 2

\[\cos A=6^{2} + 6^{2}- 8^{2}/((2)(6)(6)) =8/72=.111111\]
Angle A=83.62 degrees. The other two angles are equal to each other (isosceles triangle)
2x+83.62 = 180 degrees
2x=96.38
x=48.19, Angle b, angle c are 48.19 degrees each.